This is a quick and dirty little piece of code that returns the number of drops an item should have, given the level of fortune a player has. This gives the correct amount for coal ore, diamond ore, emerald ore, nether quartz ore, redstone ore, and lapis ore. I needed this because I wanted to override the BlockBreakEvent (which does not have access to a list of drops) and give items directly into the player's inventory. I am posting this because it was a pain to write (although it probably would have been easier with maps or something). Code: import org.bukkit.Material; import org.bukkit.enchantments.Enchantment; import org.bukkit.entity.Player; import org.bukkit.inventory.ItemStack; public class FakeFortune { private FakeFortune() {} public static int getFortuneLevel(Player player) { ItemStack tool = player.getInventory().getItemInMainHand(); return tool.getEnchantmentLevel(Enchantment.LOOT_BONUS_BLOCKS); } public static int calculateDrops(Material mat, int fortune) { double d = Math.random(); if (mat == Material.COAL_ORE || mat == Material.DIAMOND_ORE || mat == Material.EMERALD_ORE || mat == Material.NETHER_QUARTZ_ORE) { // source https://minecraft.gamepedia.com/Fortune if (fortune == 0) return 1; if (fortune == 1) { // 33% chance of 2x drops if (d < 1/3.0) return 2; return 1; } else if (fortune == 2) { // 25% chance 2x, 25% chance 3x if (d < 0.25) return 2; if (d < 0.50) return 3; return 1; } else if (fortune == 3) { // 20% chance 2x, 20% chance 3x, 20% chance 4x, 40% chance 1x if (d < 0.20) return 2; if (d < 0.40) return 3; if (d < 0.60) return 4; return 1; } } else if (mat == Material.REDSTONE_ORE) { // source: https://minecraft.gamepedia.com/Redstone_Ore if (fortune == 0) { // 50% 4, 50% 5 if (d < 0.5) return 4; return 5; } else if (fortune == 1) { // 25% 4, 25% 6, 50% 5 if (d < 0.25) return 4; if (d < 0.50) return 6; return 5; } else if (fortune == 2) { // 1/6 4, 1/6 7, 1/3 5, 1/3 6 if (d < 1/6.0) return 4; if (d < 2/6.0) return 7; if (d < 4/6.0) return 5; return 6; } else if (fortune == 3) { // 1/8 4, 1/8 8, 1/4 5, 1/4 6, 1/4 7 if (d < 1/8.0) return 4; if (d < 2/8.0) return 8; if (d < 4/8.0) return 5; if (d < 6/8.0) return 6; return 7; } } else if (mat == Material.LAPIS_ORE) { // https://minecraft.gamepedia.com/Lapis_Lazuli_Ore // im starting to think theres a better way to do this if (fortune == 0) { if (d < 1/6.0) return 4; if (d < 2/6.0) return 5; if (d < 3/6.0) return 6; if (d < 4/6.0) return 7; if (d < 5/6.0) return 8; return 9; } else if (fortune == 1) { if (d < 1/18.0) return 10; if (d < 2/18.0) return 12; if (d < 3/18.0) return 14; if (d < 4/18.0) return 16; if (d < 5/18.0) return 18; if (d < 7/18.0) return 4; if (d < 9/18.0) return 5; if (d < 11/18.0) return 6; if (d < 13/18.0) return 7; if (d < 15/18.0) return 9; // 1/6.0 = 3/18.0 return 8; } else if (fortune == 2) { if (d < 1/24.0) return 10; if (d < 2/24.0) return 14; if (d < 3/24.0) return 15; if (d < 4/24.0) return 16; if (d < 5/24.0) return 21; if (d < 6/24.0) return 24; if (d < 7/24.0) return 27; if (d < 9/24.0) return 4; if (d < 11/24.0) return 5; if (d < 13/24.0) return 6; if (d < 15/24.0) return 7; if (d < 17/24.0) return 9; if (d < 19/24.0) return 12; if (d < 21/24.0) return 18; return 8; } else if (fortune == 3) { if (d < 1/30.0) return 10; if (d < 2/30.0) return 14; if (d < 3/30.0) return 15; if (d < 4/30.0) return 20; if (d < 5/30.0) return 21; if (d < 6/30.0) return 27; if (d < 7/30.0) return 28; if (d < 8/30.0) return 32; if (d < 9/30.0) return 36; if (d < 11/30.0) return 4; if (d < 13/30.0) return 5; if (d < 15/30.0) return 6; if (d < 17/30.0) return 7; if (d < 19/30.0) return 9; if (d < 21/30.0) return 12; if (d < 23/30.0) return 16; if (d < 25/30.0) return 18; if (d < 27/30.0) return 24; // 1/10 = 3/10 return 8; } } return 1; } }
I'm pretty sure that method doesn't take fortune into account. I researched that method before and found it wouldn't give correct results. I forget the exact reason though
Question @MCMastery: Couldn't you just loop the level of fortune if for some random reason they have like fortune 1000? Just a thought.
