Ignore before and after word

How I do this ? (TOPIC NAME)

Code:java

msg = msg.replaceAll("(?i)kyll", "kill");

I tested this:

Code:java

msg = msg.replaceAll("//(?i)kyll//", "kill");

Without results

 

Your looking for help with Regular Expression, which is not what this forum is used for. Id suggest next time you use a different source for asking questions that are java related and not Bukkit related.
I find for Java (and many other languages) a great place to ask a question and get a fast response is StackOverflow.

Now, to answer your question... I do not understand what you want. Is the msg going to be 3 words and you just want the middle?

 

when he say: akyll (replace doesn't work)
Because only checking kyll, i need ignore all before and after this word.
wefwgwkyllgwegwe = wefwgwkillgwegwe

 

You dont need to actually use regex unless you need it in the parameter. So you can do this
.replaceAll("kyll", "kill");

 

without (?i) when he say KyLL doesn't replace... on msg equalsIgnoreCase doesn't work.
Alternative solution ?

 

Code:

private static final Pattern shesAKyllerQueen = Pattern.compile("kyll", Pattern.LITERAL | Pattern.CASE_INSENSITIVE);
//...
msg = shesAKyllerQueen.matcher(msg).replaceAll("kill");