cast string to enchant

how can I cast Enchantment onto the String value of the name? also, how can I run a check to see if that item is safe to have that enchantment?

 

Use the javadocs before asking such simple questions on the forums: http://jd.bukkit.org/apidocs/org/bukkit/enchantments/Enchantment.html

 

Learn to use the API.

Enchantment.getName()

 

alright, i worded that wrong. how can i cast to Enchantment FROM a string? and check if it's a safe enchant for the item?

 

Enchantment.getByName();
Enchantment.canEnchantItem();
Still didn't look at the API docs, huh? Cool.

​

 

i guess I just don't get it, cause the docs isn't making anything click no matter how many times i read em.... maybe this will help, here's my code.... and my errors...

Code:

    public static void giveKit(KitKat plugin, Player player, String kitName) {
        List<String> itemList = plugin.getConfig().getStringList("kits." + kitName + ".items");
        ListIterator<String> it = itemList.listIterator();
        if (it.hasNext()) {
            while (it.hasNext()) {
                String[] item = it.next().split(" ");
                int id = Integer.parseInt(item[0]);
                short meta = (short) Integer.parseInt(item[1]);
                int amount = Integer.parseInt(item[2]);
                ItemStack stack = new ItemStack(id, amount, meta);
                if (!item[3].contains("none")) {
                    int level = Integer.parseInt(item[4]);
                    Enchantment enchant = Enchantment.getByName(item[3].toUpperCase());
                    stack.addEnchantment(enchant, level);
                }
                player.getInventory().addItem(stack);
            }
        }
    }

Code:

kits:
    tools:
        items:
        - 269 0 1 SILK_TOUCH 4
        - 270 0 1 none 0
        - 271 0 1 none 0
        - 290 0 1 none 0
        cooldown: 1200

 

Well your error there is completely unrelated to what you were asking. You're getting that because you're trying to access an index in an array that doesn't exist.